What is the domain of ((2x^2-x-8))/(x^2+1) ?

The domain of ((2x^2-x-8))/(x^2+1) is -infinity <x<infinity

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domain of ((2x^2-x-8))/(x^2+1)

domain

\frac{( 2 x ^{2} - x - 8 )}{x ^{2} + 1}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = (x - 2)^{2} - 1

f (x) = \frac{x + 3}{x - 7}

y = - 2 x + 1

f (x) = 9 + (2 + x)^{\frac{1}{2}}

y = 1 - \frac{x}{9}

What is the domain of ((2x^2-x-8))/(x^2+1) ?
The domain of ((2x^2-x-8))/(x^2+1) is -infinity <x<infinity