What is the range of f(x)=1+(4+x)^{1/2} ?

The range of f(x)=1+(4+x)^{1/2} is f(x)>= 1

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range of f(x)=1+(4+x)^{1/2}

range

f (x) = 1 + (4 + x)^{\frac{1}{2}}

f (x) \geq 1

Interval Notation

[1, \infty)

Solution steps

The range of an radical function of the form

c a x + b + k

f (x) \geq k

k = 1

f (x) \geq 1

f (x) = (ln (t - 2))

- x + 4 - 1

f (x) = (x + 5)^{5}

f (x) = x^{2} - 5 x + 4

g (x) = x^{3}

What is the range of f(x)=1+(4+x)^{1/2} ?
The range of f(x)=1+(4+x)^{1/2} is f(x)>= 1