What is the domain of f(x)=(sqrt(x+7))/(x-5) ?

The domain of f(x)=(sqrt(x+7))/(x-5) is -7 5

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domain of f(x)=(sqrt(x+7))/(x-5)

domain

f (x) = \frac{x + 7}{x - 5}

- 7 \leq x < 5 or x > 5

Interval Notation

[- 7, 5) \cup (5, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 7

Find undefined (singularity) points:

x = 5

Combine real regions and undefined points for final function domain

- 7 \leq x < 5 or x > 5

f (x) = 2 (y - 1) (y - 2) (y - 3)

3 sin (\frac{2 π θ}{5})

\frac{x ^{2} - x - 12}{2 x - 8}

(- 2, 1), (4, 9)

\frac{x - 4}{3 x + 7}

What is the domain of f(x)=(sqrt(x+7))/(x-5) ?
The domain of f(x)=(sqrt(x+7))/(x-5) is -7<= x<5\lor x>5