What is the domain of f(x)=sqrt(4x-32) ?

The domain of f(x)=sqrt(4x-32) is x>= 8

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domain of f(x)=sqrt(4x-32)

domain

f (x) = 4 x - 32

x \geq 8

Interval Notation

[8, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 8

The function domain

x \geq 8

\frac{- 2 x - 7}{3 x - 1}

3 y = - 2 x + 6, (2, 2)

f (x) = \frac{2}{x - 3 - 1}

\frac{sin ( 2 x )}{x + tan ( 8 x )}

y = 5 x^{5} - 7 x^{3}

What is the domain of f(x)=sqrt(4x-32) ?
The domain of f(x)=sqrt(4x-32) is x>= 8