What is the inverse of f(x)=(x+3)^2-8 ?

The inverse of f(x)=(x+3)^2-8 is sqrt(x+8)-3,-sqrt(x+8)-3

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inverse of f(x)=(x+3)^2-8

inverse

f (x) = (x + 3)^{2} - 8

x + 8 - 3, - x + 8 - 3

Solution steps

y = (x + 3)^{2} - 8

Replace

x

with

y

x = (y + 3)^{2} - 8

Solve for

y, x = (y + 3)^{2} - 8

x + 8 - 3, - x + 8 - 3

f (x) = x^{2} + 12 x + 40

f (x) = (lo g_{2} (x)) + 8

f (x) = 2 \cdot 3^{x}

(- 4.8) (- 2.1)

f (x) = \frac{4 x ^{2} + x - 9}{x ^{2} + x - 56}

What is the inverse of f(x)=(x+3)^2-8 ?
The inverse of f(x)=(x+3)^2-8 is sqrt(x+8)-3,-sqrt(x+8)-3