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Popular >

distance (0,-5),(6,1)

Solution

distance

(0, - 5), (6, 1)

Solution

62

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(0, - 5)

and

(6, 1)

is

= (6 - 0)^{2} + (1 - (- 5))^{2}

Simplify

= 62

Popular Examples

domain of cos(4x)domain

cos (4 x)

domain of f(x)= 1/(x-3)+2 domain

f (x) = \frac{1}{x - 3} + 2

domain of f(x)=(-3)/(12-x-x^2)domain

f (x) = \frac{- 3}{12 - x - x ^{2}}

inflection f(x)=ln(1+x)inflection points

f (x) = ln (1 + x)

domain of f(x)=e^{4sqrt(x)}domain

f (x) = e^{4 x}

Frequently Asked Questions (FAQ)

What is the distance (0,-5),(6,1) ?
The distance (0,-5),(6,1) is 6sqrt(2)