What is the asymptotes of y= 1/(x^2-9) ?

The asymptotes of y= 1/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of y= 1/(x^2-9)

asymptotes

y = \frac{1}{x ^{2} - 9}

Vertical : x = - 3, x = 3, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{1}{x ^{2} - 9} : x = - 3, x = 3

Horizontal Asymptotes of

\frac{1}{x ^{2} - 9} : y = 0

Slant Asymptotes of

\frac{1}{x ^{2} - 9} :

None

Vertical : x = - 3, x = 3, Horizontal : y = 0

\frac{9}{x - 4}

f (x) = \frac{x ^{2} - 4 x - 21}{3 x - 21}

y = \frac{x ^{2} - 16}{9 - x ^{2}}

f (x) = \frac{1}{1 - e ^{x}}

f (x) = - x^{4} + 4 x^{3} + 2

What is the asymptotes of y= 1/(x^2-9) ?
The asymptotes of y= 1/(x^2-9) is Vertical: x=-3,x=3,Horizontal: y=0