What is the extreme f(x)=x^3-12x+1 ?

The extreme f(x)=x^3-12x+1 is Maximum(-2,17),Minimum(2,-15)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^3-12x+1

extreme points

f (x) = x^{3} - 12 x + 1

Maximum (- 2, 17), Minimum (2, - 15)

Solution steps

f^{'} (x) = 3 x^{2} - 12

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

x^{3} - 12 x + 1 : 17

Maximum (- 2, 17)

Plug

x = 2

into

x^{3} - 12 x + 1 : - 15

Minimum (2, - 15)

Maximum (- 2, 17), Minimum (2, - 15)

\frac{4 x + 9}{3 x - 2}

x + 2 y = 16

x^{2} - 2 x - 35

f (x) = \frac{9}{x} + x + 1

f (x) = - \frac{1313}{2050} x + \frac{6963}{5125}

What is the extreme f(x)=x^3-12x+1 ?
The extreme f(x)=x^3-12x+1 is Maximum(-2,17),Minimum(2,-15)