What is the perpendicular 3x+2y+3=0 ?

The perpendicular 3x+2y+3=0 is y= 2/3 x+b

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

perpendicular 3x+2y+3=0

perpendicular

3 x + 2 y + 3 = 0

y = \frac{2}{3} x + b

Solution steps

Find the slope of

3 x + 2 y + 3 = 0 : m = - \frac{3}{2}

Compute the slope of the perpendicular line:

m_{p} = \frac{2}{3}

Line with slope m=

\frac{2}{3} : y = \frac{2}{3} x + b

y = \frac{2}{3} x + b

\frac{x - 2}{x + 4}

f (x) = - 7 x + 7

f (x) = - 5 x + 3

csc (\frac{( x \cdot π )}{2}) + 1

f (x) = \frac{- 5 x - 10}{x ^{2} + 2 x}