What is the inverse of f(x)=-0.025x^2+0.35x ?

The inverse of f(x)=-0.025x^2+0.35x is 7-sqrt(-40x+49),sqrt(-40x+49)+7

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inverse of f(x)=-0.025x^2+0.35x

inverse

f (x) = - 0.025 x^{2} + 0.35 x

7 - - 40 x + 49, - 40 x + 49 + 7

Solution steps

y = - 0.025 x^{2} + 0.35 x

Replace

x

with

y

x = - 0.025 y^{2} + 0.35 y

Solve for

y, x = - 0.025 y^{2} + 0.35 y

7 - - 40 x + 49, - 40 x + 49 + 7

y = 5

f (x) = \frac{sin ( x )}{1 + cos ( x )}

x e^{- \frac{x ^{2}}{2}}

f (x) = \frac{9 + x}{3}

3 x^{6} - 7 x^{5}

What is the inverse of f(x)=-0.025x^2+0.35x ?
The inverse of f(x)=-0.025x^2+0.35x is 7-sqrt(-40x+49),sqrt(-40x+49)+7