What is the perpendicular x-9y-8=0,(1,-4) ?

The perpendicular x-9y-8=0,(1,-4) is y=-9x+5

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perpendicular x-9y-8=0,(1,-4)

perpendicular

x - 9 y - 8 = 0, (1, - 4)

y = - 9 x + 5

Solution steps

Find the line

y = mx + b

perpendicular to

x - 9 y - 8 = 0

that passes through

(1, - 4)

Find the slope of

x - 9 y - 8 = 0 : m = \frac{1}{9}

Compute the slope of the perpendicular line:

m_{p} = - 9

Find the line with slope m=

- 9

and passing through

(1, - 4) : y = - 9 x + 5

y = - 9 x + 5

f (x) = - \frac{1}{2 3 - x}

f (x) = \frac{5 x + 25}{2 x + 10}

4 x - y = 3

(2, 9), (7, 8)

y = x^{4} + 2 x^{3} - 2 x^{2} + 1

What is the perpendicular x-9y-8=0,(1,-4) ?
The perpendicular x-9y-8=0,(1,-4) is y=-9x+5