What is the inverse of f(x)= 1/2 x^3+1/2 ?

The inverse of f(x)= 1/2 x^3+1/2 is cube root of 2x-1

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inverse of f(x)= 1/2 x^3+1/2

inverse

f (x) = \frac{1}{2} x^{3} + \frac{1}{2}

Solution steps

y = \frac{1}{2} x^{3} + \frac{1}{2}

Replace

x

with

y

x = \frac{1}{2} y^{3} + \frac{1}{2}

Solve for

y, x = \frac{1}{2} y^{3} + \frac{1}{2}

f (x) = x^{4} + 1

f (x) = \frac{x - 2}{x - 1}

f (x) = \frac{x - 3}{3 x + 5}

f (x) = 1 - x

f (x) = 2^{(x - 3)}

What is the inverse of f(x)= 1/2 x^3+1/2 ?
The inverse of f(x)= 1/2 x^3+1/2 is cube root of 2x-1