What is the domain of f(x)=arctan(1+1/x) ?

The domain of f(x)=arctan(1+1/x) is x 0

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domain of f(x)=arctan(1+1/x)

domain

f (x) = arctan (1 + \frac{1}{x})

x < 0 or x > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0

The function domain

x < 0 or x > 0

f (x) = 6 x + 24

f (x) = \frac{1}{x ^{2} + 1}

h (x) = \frac{4}{x - 5}

y = 4 x + 2, (- 8, 5)

sin^{2} (16 x)

What is the domain of f(x)=arctan(1+1/x) ?
The domain of f(x)=arctan(1+1/x) is x<0\lor x>0