What is the domain of f(x)=sqrt(4x+2) ?

The domain of f(x)=sqrt(4x+2) is x>=-1/2

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domain of f(x)=sqrt(4x+2)

domain

f (x) = 4 x + 2

x \geq - \frac{1}{2}

Interval Notation

[- \frac{1}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{1}{2}

The function domain

x \geq - \frac{1}{2}

f (x) = x + 2 - 3

f (x) = \frac{x ^{2} + 4 x - 32}{x ^{2} - 16}

f (x) = \frac{1}{( x + 3 ) ^{2}}

f (x) = \frac{x ^{2} - 2 x + 1}{x + 1}

f (x) = (x - 10) 3 + 4

What is the domain of f(x)=sqrt(4x+2) ?
The domain of f(x)=sqrt(4x+2) is x>=-1/2