What is the perpendicular 10x+4y=-56 ?

The perpendicular 10x+4y=-56 is y= 2/5 x+b

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perpendicular 10x+4y=-56

perpendicular

10 x + 4 y = - 56

y = \frac{2}{5} x + b

Solution steps

Find the slope of

10 x + 4 y = - 56 : m = - \frac{5}{2}

Compute the slope of the perpendicular line:

m_{p} = \frac{2}{5}

Line with slope m=

\frac{2}{5} : y = \frac{2}{5} x + b

y = \frac{2}{5} x + b

f (x) = \frac{3 x + 2}{4 + x}

f (x) = \frac{1}{x - 7}

y = \frac{e ^{x}}{1 + 9 e ^{x}}

f (x) = x^{2} + 3 x

1 + 3.22 ln (34)

What is the perpendicular 10x+4y=-56 ?
The perpendicular 10x+4y=-56 is y= 2/5 x+b