What is the perpendicular 2x+3y=7,(4,3) ?

The perpendicular 2x+3y=7,(4,3) is y= 3/2 x-3

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perpendicular 2x+3y=7,(4,3)

perpendicular

2 x + 3 y = 7, (4, 3)

y = \frac{3}{2} x - 3

Solution steps

Find the line

y = mx + b

perpendicular to

2 x + 3 y = 7

that passes through

(4, 3)

Find the slope of

2 x + 3 y = 7 : m = - \frac{2}{3}

Compute the slope of the perpendicular line:

m_{p} = \frac{3}{2}

Find the line with slope m=

\frac{3}{2}

and passing through

(4, 3) : y = \frac{3}{2} x - 3

y = \frac{3}{2} x - 3

f (x) = \frac{x + 2}{x ^{2} + 5 x + 6}

f (x) = x + 5 - 4

x^{2} + 2 x + 2

2 sin (2 x) + 3

f (x) = ln (\frac{5 x - x ^{2}}{4})

What is the perpendicular 2x+3y=7,(4,3) ?
The perpendicular 2x+3y=7,(4,3) is y= 3/2 x-3