What is the inverse of f(x)=18500(0.16-r^2) ?

The inverse of f(x)=18500(0.16-r^2) is sqrt(-0.00005…r+0.16),-sqrt(-0.00005…r+0.16)

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inverse of f(x)=18500(0.16-r^2)

inverse

f (x) = 18500 (0.16 - r^{2})

- 0.00005 \dots r + 0.16, - - 0.00005 \dots r + 0.16

Solution steps

x = 18500 (0.16 - r^{2})

Replace

r

with

x

r = 18500 (0.16 - x^{2})

Solve for

x, r = 18500 (0.16 - x^{2})

- 0.00005 \dots r + 0.16, - - 0.00005 \dots r + 0.16

f (x) = ∣ x ∣ + 2

f (x) = 2 x + 7

f (x) = (x - 3)^{2} - 7

f (x) = \frac{1}{x ^{2} - 5 x + 6}

y = - 2 x + 2

What is the inverse of f(x)=18500(0.16-r^2) ?
The inverse of f(x)=18500(0.16-r^2) is sqrt(-0.00005…r+0.16),-sqrt(-0.00005…r+0.16)