What is the critical f(x)=0.05x+20+(125)/x ?

The critical f(x)=0.05x+20+(125)/x is x=-50,x=50

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critical f(x)=0.05x+20+(125)/x

critical points

f (x) = 0.05 x + 20 + \frac{125}{x}

x = - 50, x = 50

Solution steps

0.05 x + 20 + \frac{125}{x}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 50, x = 50, x = 0

Identify critical points not in

f (x)

domain

Domain of

0.05 x + 20 + \frac{125}{x} : x < 0 or x > 0

0.05 x + 20 + \frac{125}{x}

is not defined at

x = 0

, therefore:

x = - 50, x = 50

y = 1. 5^{x} + 4

f (x) = - 3 x + 6

f (x) = x x + 1

\frac{x + 7}{x ^{2} + 7 x + 6}

sin (x) cos (x)

What is the critical f(x)=0.05x+20+(125)/x ?
The critical f(x)=0.05x+20+(125)/x is x=-50,x=50