What is the domain of f(x)=sqrt(2x-1) ?

The domain of f(x)=sqrt(2x-1) is x>= 1/2

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domain of f(x)=sqrt(2x-1)

domain

f (x) = 2 x - 1

x \geq \frac{1}{2}

Interval Notation

[\frac{1}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{2}

The function domain

x \geq \frac{1}{2}

f (x) = 3 - \frac{1}{x ^{2} + 1}

f (x) = \frac{( 2 x + 3 )}{5 x - 1}

y = \frac{5}{9} (x - 32)

f (x) = 1 - 8 x^{3}

\frac{x - 2}{( x + 4 ) ^{2}}

What is the domain of f(x)=sqrt(2x-1) ?
The domain of f(x)=sqrt(2x-1) is x>= 1/2