What is the domain of f(x)=(sqrt(x+4))/(x-8) ?

The domain of f(x)=(sqrt(x+4))/(x-8) is -4 8

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domain of f(x)=(sqrt(x+4))/(x-8)

domain

f (x) = \frac{x + 4}{x - 8}

- 4 \leq x < 8 or x > 8

Interval Notation

[- 4, 8) \cup (8, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 4

Find undefined (singularity) points:

x = 8

Combine real regions and undefined points for final function domain

- 4 \leq x < 8 or x > 8

y = \frac{2}{5} x - 3

x^{2} - 6 x - 7

f (x) = \frac{x - 1}{x + 1}

(- 9, - 4), (- 3, 6)

∣ 3 x - 5 ∣

What is the domain of f(x)=(sqrt(x+4))/(x-8) ?
The domain of f(x)=(sqrt(x+4))/(x-8) is -4<= x<8\lor x>8