en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

range of f(x)=2x^2-7x-4

Solution

range

f (x) = 2 x^{2} - 7 x - 4

Solution

f (x) \geq - \frac{81}{8}

+1

Interval Notation

[- \frac{81}{8}, \infty)

Solution steps

Vertex of

2 x^{2} - 7 x - 4 :

Minimum

(\frac{7}{4}, - \frac{81}{8})

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 2,

Vertex

(x_{v}, y_{v}) = (\frac{7}{4}, - \frac{81}{8})

f (x) \geq - \frac{81}{8}

Popular Examples

critical f(x)=-x^3+2x^2+2 critical points

f (x) = - x^{3} + 2 x^{2} + 2

domain of f(x)= 2/((x^2+4))domain

f (x) = \frac{2}{( x ^{2} + 4 )}

distance (-4,-3),(2,5)distance

(- 4, - 3), (2, 5)

inverse of f(x)=x^{3/5}inverse

f (x) = x^{\frac{3}{5}}

inverse of f(x)=-x^2+2x+3 inverse

f (x) = - x^{2} + 2 x + 3

Frequently Asked Questions (FAQ)

What is the range of f(x)=2x^2-7x-4 ?
The range of f(x)=2x^2-7x-4 is f(x)>=-81/8