What is the domain of f(x)=(x^2)/(x^2-x-12) ?

The domain of f(x)=(x^2)/(x^2-x-12) is x 4

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domain of f(x)=(x^2)/(x^2-x-12)

domain

f (x) = \frac{x ^{2}}{x ^{2} - x - 12}

x < - 3 or - 3 < x < 4 or x > 4

Interval Notation

(- \infty, - 3) \cup (- 3, 4) \cup (4, \infty)

Solution steps

Find undefined (singularity) points:

x = 4, x = - 3

The function domain

x < - 3 or - 3 < x < 4 or x > 4

2 x - 17

x - y = - 6

f (x) = \frac{( 2 x + 3 )}{x - 8}

f (x) = (x + 7)^{2} - 3

f (x) = 3 - \frac{12}{x + 2}

What is the domain of f(x)=(x^2)/(x^2-x-12) ?
The domain of f(x)=(x^2)/(x^2-x-12) is x<-3\lor-3<x<4\lor x>4