What is the domain of 1/(x^2-2) ?

The domain of 1/(x^2-2) is x sqrt(2)

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domain of 1/(x^2-2)

domain

\frac{1}{x ^{2} - 2}

x < - 2 or - 2 < x < 2 or x > 2

Interval Notation

(- \infty, - 2) \cup (- 2, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 2

The function domain

x < - 2 or - 2 < x < 2 or x > 2

3 x + 4 y = 5, at (\frac{- 2 , 4}{7})

f (x) = x^{2} + 11

lo g_{4} (x^{3} + 2)

6 - \frac{1}{2} x

y = - 3 x + 1

What is the domain of 1/(x^2-2) ?
The domain of 1/(x^2-2) is x<-sqrt(2)\lor-sqrt(2)<x<sqrt(2)\lor x>sqrt(2)