What is the inverse of f(x)=(x-8)/(1+7x) ?

The inverse of f(x)=(x-8)/(1+7x) is (-8-x)/(7x-1)

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inverse of f(x)=(x-8)/(1+7x)

inverse

f (x) = \frac{x - 8}{1 + 7 x}

\frac{- 8 - x}{7 x - 1}

Solution steps

y = \frac{x - 8}{1 + 7 x}

Replace

x

with

y

x = \frac{y - 8}{1 + 7 y}

Solve for

y, x = \frac{y - 8}{1 + 7 y}

\frac{- 8 - x}{7 x - 1}

\frac{1}{1 + s ^{3}}

16 - x^{2} - x + 1

f (x) = 5 - x - x^{2} - 4

3 x^{3} - 9 x + 1

3 cos (4 x)

What is the inverse of f(x)=(x-8)/(1+7x) ?
The inverse of f(x)=(x-8)/(1+7x) is (-8-x)/(7x-1)