What is the inverse of f(x)=(sqrt(2x-7))/3 ?

The inverse of f(x)=(sqrt(2x-7))/3 is (9x^2+7)/2

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inverse of f(x)=(sqrt(2x-7))/3

inverse

f (x) = \frac{2 x - 7}{3}

\frac{9 x ^{2} + 7}{2}

Solution steps

y = \frac{2 x - 7}{3}

Replace

x

with

y

x = \frac{2 y - 7}{3}

Solve for

y, x = \frac{2 y - 7}{3}

\frac{9 x ^{2} + 7}{2}

f (x) = 3 x^{2} + 6 x

lo g_{3} (x)

\frac{1}{x} + 1

f (x) = \frac{x - 1}{x ^{2} - 3 x - 4}

f (x) = ln (x) + 6

What is the inverse of f(x)=(sqrt(2x-7))/3 ?
The inverse of f(x)=(sqrt(2x-7))/3 is (9x^2+7)/2