What is the domain of f(x)= 6/(sqrt(4-x^2)) ?

The domain of f(x)= 6/(sqrt(4-x^2)) is -2<x<2

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domain of f(x)= 6/(sqrt(4-x^2))

domain

f (x) = \frac{6}{4 - x ^{2}}

- 2 < x < 2

Interval Notation

(- 2, 2)

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 2

Find undefined (singularity) points:

x = 2, x = - 2

Combine real regions and undefined points for final function domain

- 2 < x < 2

\frac{1}{4} x - \frac{1}{6}

f (x) = \frac{3 x}{( x - 6 ) ( x + 4 )}

f (x) = 0

f (x) = \frac{x ^{2}}{x + 6}

f (x) = x^{3} - 27 x + 8

What is the domain of f(x)= 6/(sqrt(4-x^2)) ?
The domain of f(x)= 6/(sqrt(4-x^2)) is -2<x<2