What is the domain of f(x)=sqrt(x(x-1)(x+1)) ?

The domain of f(x)=sqrt(x(x-1)(x+1)) is -1 = 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(x(x-1)(x+1))

domain

f (x) = x (x - 1) (x + 1)

- 1 \leq x \leq 0 or x \geq 1

Interval Notation

[- 1, 0] \cup [1, \infty)

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 0 or x \geq 1

The function domain

- 1 \leq x \leq 0 or x \geq 1

2 x - 4 y = - 5, (- 2, 4)

\frac{5}{3}

\frac{1}{t} + 1

\frac{9 x}{x}

x + 2 y = 3

What is the domain of f(x)=sqrt(x(x-1)(x+1)) ?
The domain of f(x)=sqrt(x(x-1)(x+1)) is -1<= x<= 0\lor x>= 1