What is the asymptotes of f(x)=(3x^2)/(2x^2-32) ?

The asymptotes of f(x)=(3x^2)/(2x^2-32) is Vertical: x=-4,x=4,Horizontal: y= 3/2

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asymptotes of f(x)=(3x^2)/(2x^2-32)

asymptotes

f (x) = \frac{3 x ^{2}}{2 x ^{2} - 32}

Vertical : x = - 4, x = 4, Horizontal : y = \frac{3}{2}

Solution steps

Vertical asymptotes of

\frac{3 x ^{2}}{2 x ^{2} - 32} : x = - 4, x = 4

Horizontal Asymptotes of

\frac{3 x ^{2}}{2 x ^{2} - 32} : y = \frac{3}{2}

Slant Asymptotes of

\frac{3 x ^{2}}{2 x ^{2} - 32} :

None

Vertical : x = - 4, x = 4, Horizontal : y = \frac{3}{2}

y = \frac{4 x - 2}{3 x + 1}

f (x) = \frac{1}{2} cos (2 x)

f (t) = 17 - 1.2 t

x^{2} + 2 x - 5

y = ln (x^{4} sin^{2} (x))

What is the asymptotes of f(x)=(3x^2)/(2x^2-32) ?
The asymptotes of f(x)=(3x^2)/(2x^2-32) is Vertical: x=-4,x=4,Horizontal: y= 3/2