What is the inverse of f(x)=(x+3)^2,x<=-3 ?

The inverse of f(x)=(x+3)^2,x<=-3 is sqrt(x)-3,-sqrt(x)-3

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inverse of f(x)=(x+3)^2,x<=-3

inverse

f (x) = (x + 3)^{2}, x \leq - 3

x - 3, - x - 3

Solution steps

y = (x + 3)^{2}

Replace

x

with

y

x = (y + 3)^{2}

Solve for

y, x = (y + 3)^{2}

x - 3, - x - 3

f (x) = x e^{\frac{1}{x}}

f (x, y) = x

\frac{x + x}{( 1 + 2 ln ( 2 x ) )}

f (x) = x^{2} - 4 x - 2

y = ln (x + 2)

What is the inverse of f(x)=(x+3)^2,x<=-3 ?
The inverse of f(x)=(x+3)^2,x<=-3 is sqrt(x)-3,-sqrt(x)-3