What is the shift y=-2sin(4x+pi/2) ?

The shift y=-2sin(4x+pi/2) is Phase:-pi/8 , Vertical:0

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shift y=-2sin(4x+pi/2)

shift

y = - 2 sin (4 x + \frac{π}{2})

Phase : - \frac{π}{8}, Vertical : 0

Solution steps

f (x) = - 2 sin (4 x + \frac{π}{2})

g (B x - C) = sin (4 x + \frac{π}{2}), B = 4, C = - \frac{π}{2}, D = 0

Therefore, the phase shift

\frac{C}{B}

\frac{- \frac{π}{2}}{4}

- \frac{π}{8}

The vertical shift

D

0

0

ln (x - 5)

f (x) = \frac{1}{2} x^{2} + 4 x + 5

f (x) = 3 x - 6

4 - x

2 x^{2} + 4 x - 1

What is the shift y=-2sin(4x+pi/2) ?
The shift y=-2sin(4x+pi/2) is Phase:-pi/8 , Vertical:0