What is the inverse of f(x)=(x-5)^2+3 ?

The inverse of f(x)=(x-5)^2+3 is sqrt(x-3)+5,-sqrt(x-3)+5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(x-5)^2+3

inverse

f (x) = (x - 5)^{2} + 3

x - 3 + 5, - x - 3 + 5

Solution steps

y = (x - 5)^{2} + 3

Replace

x

with

y

x = (y - 5)^{2} + 3

Solve for

y, x = (y - 5)^{2} + 3

x - 3 + 5, - x - 3 + 5

e^{x + 6}

g (x) = \frac{- x - 5}{3}

4 sin (6 x - π)

f (x) = \frac{- 4 - 5 x}{3 x - 1}

f (x) = 3 x^{2} + 5

What is the inverse of f(x)=(x-5)^2+3 ?
The inverse of f(x)=(x-5)^2+3 is sqrt(x-3)+5,-sqrt(x-3)+5