What is the domain of f(x)= 1/(6sqrt(2x+16)-12) ?

The domain of f(x)= 1/(6sqrt(2x+16)-12) is -8 -6

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domain of f(x)= 1/(6sqrt(2x+16)-12)

domain

f (x) = \frac{1}{6 2 x + 16 - 12}

- 8 \leq x < - 6 or x > - 6

Interval Notation

[- 8, - 6) \cup (- 6, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 8

Find undefined (singularity) points:

x = - 6

Combine real regions and undefined points for final function domain

- 8 \leq x < - 6 or x > - 6

f (x) = \frac{4}{x + 10}

f (x) = \frac{5 x}{x ^{2} - 9}

4 x^{2}

(1.5, 4.5), (1, 3)

y = x^{2} - 6 x + 9

What is the domain of f(x)= 1/(6sqrt(2x+16)-12) ?
The domain of f(x)= 1/(6sqrt(2x+16)-12) is -8<= x<-6\lor x>-6