What is the critical f(x)=((x-8))/((x+6)) ?

The critical f(x)=((x-8))/((x+6)) is None

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critical f(x)=((x-8))/((x+6))

critical points

f (x) = \frac{( x - 8 )}{( x + 6 )}

None

Solution steps

\frac{x - 8}{x + 6}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 6

Identify critical points not in

f (x)

domain

Domain of

\frac{x - 8}{x + 6} : x < - 6 or x > - 6

\frac{x - 8}{x + 6}

is not defined at

x = - 6

, therefore:

None

\frac{x ^{2} - 9}{x - 5}

f (x) = \frac{36 - x ^{2}}{36}

y = 6 sec (x^{2})

f (x) = x^{3} + 2

f (x) = \frac{x ^{2}}{x ^{2} + x - 6}

What is the critical f(x)=((x-8))/((x+6)) ?
The critical f(x)=((x-8))/((x+6)) is None