What is the inflection f(x)=16x^4-96x^2 ?

The inflection f(x)=16x^4-96x^2 is (-1,-80),(1,-80)

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inflection f(x)=16x^4-96x^2

inflection points

f (x) = 16 x^{4} - 96 x^{2}

(- 1, - 80), (1, - 80)

Solution steps

f^{''} (x) = 192 x^{2} - 192

Find intervals:

Concave Upward

: - \infty < x < - 1,

Concave Downward

: - 1 < x < 1,

Concave Upward

: 1 < x < \infty

Plug

x = - 1

into

16 x^{4} - 96 x^{2} : - 80

(- 1, - 80)

Plug

x = 1

into

16 x^{4} - 96 x^{2} : - 80

(1, - 80)

(- 1, - 80), (1, - 80)

y = 4 - x

f (x) = x^{x}

\frac{- 2 x ^{2}}{( x - 3 ) ( x + 2 )}

6 x + 2 y = - 2

(- 4, - 8), (1, - 5)

What is the inflection f(x)=16x^4-96x^2 ?
The inflection f(x)=16x^4-96x^2 is (-1,-80),(1,-80)