What is the inverse of f(x)=3log_{4}(x+1)-3 ?

The inverse of f(x)=3log_{4}(x+1)-3 is 4^{(x+3)/3}-1

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inverse of f(x)=3log_{4}(x+1)-3

inverse

f (x) = 3 lo g_{4} (x + 1) - 3

4^{\frac{x + 3}{3}} - 1

Solution steps

y = 3 lo g_{4} (x + 1) - 3

Replace

x

with

y

x = 3 lo g_{4} (y + 1) - 3

Solve for

y, x = 3 lo g_{4} (y + 1) - 3

4^{\frac{x + 3}{3}} - 1

y = ln (x + 3) - 1

7 x (x + 1)

f (x) = \frac{x ^{3}}{x ^{2} - x}

x^{3} - x + 1

f (x) = \frac{x + 1}{x - 2}

What is the inverse of f(x)=3log_{4}(x+1)-3 ?
The inverse of f(x)=3log_{4}(x+1)-3 is 4^{(x+3)/3}-1