What is the domain of sqrt(x^2-36) ?

The domain of sqrt(x^2-36) is x = 6

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domain of sqrt(x^2-36)

domain

x^{2} - 36

x \leq - 6 or x \geq 6

Interval Notation

(- \infty, - 6] \cup [6, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 6 or x \geq 6

The function domain

x \leq - 6 or x \geq 6

f (x) = - x^{2} + 8

\frac{2 x + 3}{x + 1}

2 x - 8

f (x) = - \frac{21}{( 4 + x ) ^{2}}

f (x) = sin (π + 4 x)

What is the domain of sqrt(x^2-36) ?
The domain of sqrt(x^2-36) is x<=-6\lor x>= 6