What is the critical f(x)=2.5+2.2x-0.6x^2 ?

The critical f(x)=2.5+2.2x-0.6x^2 is x= 11/6

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critical f(x)=2.5+2.2x-0.6x^2

critical points

f (x) = 2.5 + 2.2 x - 0.6 x^{2}

x = \frac{11}{6}

Solution steps

2.5 + 2.2 x - 0.6 x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{11}{6}

Identify critical points not in

f (x)

domain

Domain of

2.5 + 2.2 x - 0.6 x^{2} : - \infty < x < \infty

All critical points are in domain

x = \frac{11}{6}

4 x - 16

\frac{x ^{2} - 1}{x ^{2} + 1}

f (x) = \frac{( x - 9 )}{2}

(6, 3), (- 3, 4)

f (x) = x^{2} - 5 x - 6

What is the critical f(x)=2.5+2.2x-0.6x^2 ?
The critical f(x)=2.5+2.2x-0.6x^2 is x= 11/6