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Popular >

distance (-5,-5),(-9,-2)

Solution

distance

(- 5, - 5), (- 9, - 2)

Solution

5

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(- 5, - 5)

and

(- 9, - 2)

is

= (- 9 - (- 5))^{2} + (- 2 - (- 5))^{2}

Simplify

= 5

Popular Examples

critical f(x)=(x-5)^{4/5}critical points

f (x) = (x - 5)^{\frac{4}{5}}

domain of f(x)=sqrt(5-x)+sqrt(6+x)domain

f (x) = 5 - x + 6 + x

shift f(x)=4sin(2x-pi/3)+1 shift

f (x) = 4 sin (2 x - \frac{π}{3}) + 1

range of (3x)/(x+2)range

\frac{3 x}{x + 2}

domain of f(x)=x^2-11,x>= 0 domain

f (x) = x^{2} - 11, x \geq 0

Frequently Asked Questions (FAQ)

What is the distance (-5,-5),(-9,-2) ?
The distance (-5,-5),(-9,-2) is 5