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Popular >

range of f(x)=2x^2+20x+48

Solution

range

f (x) = 2 x^{2} + 20 x + 48

Solution

f (x) \geq - 2

+1

Interval Notation

[- 2, \infty)

Solution steps

Vertex of

2 x^{2} + 20 x + 48 :

Minimum

(- 5, - 2)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 2,

Vertex

(x_{v}, y_{v}) = (- 5, - 2)

f (x) \geq - 2

Popular Examples

intercepts of (-2x-9)/(4x-19)intercepts

\frac{- 2 x - 9}{4 x - 19}

asymptotes of f(x)=(3-3x)/(x-5)asymptotes

f (x) = \frac{3 - 3 x}{x - 5}

domain of sqrt(-x+9)domain

- x + 9

range of (x+1)^2 range

(x + 1)^{2}

inverse of f(x)=(sqrt(3x+2))/4 inverse

f (x) = \frac{3 x + 2}{4}

Frequently Asked Questions (FAQ)

What is the range of f(x)=2x^2+20x+48 ?
The range of f(x)=2x^2+20x+48 is f(x)>=-2