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Popular >

range of f(x)=x^2-4x+8

Solution

range

f (x) = x^{2} - 4 x + 8

Solution

f (x) \geq 4

+1

Interval Notation

[4, \infty)

Solution steps

Vertex of

x^{2} - 4 x + 8 :

Minimum

(2, 4)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (2, 4)

f (x) \geq 4

Popular Examples

domain of f(x)=sqrt((5+x)/(5-x))domain

f (x) = \frac{5 + x}{5 - x}

intercepts of f(x)=(x+6)/(x^2-3x-18)intercepts

f (x) = \frac{x + 6}{x ^{2} - 3 x - 18}

domain of 4/((x+1)^2-1)domain

\frac{4}{( x + 1 ) ^{2} - 1}

intercepts of f(x)=((x^2+25))/x intercepts

f (x) = \frac{( x ^{2} + 25 )}{x}

domain of y=4x+3 domain

y = 4 x + 3

Frequently Asked Questions (FAQ)

What is the range of f(x)=x^2-4x+8 ?
The range of f(x)=x^2-4x+8 is f(x)>= 4