What is the range of f(x)=((x-1))/(x+1) ?

The range of f(x)=((x-1))/(x+1) is f(x) 1

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range of f(x)=((x-1))/(x+1)

range

f (x) = \frac{( x - 1 )}{x + 1}

f (x) < 1 or f (x) > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{x - 1}{x + 1}

Inverse of

\frac{x - 1}{x + 1} : \frac{- 1 - x}{x - 1}

\frac{- 1 - x}{x - 1}

Find the domain of each inverse function

Domain of

\frac{- 1 - x}{x - 1} : x < 1 or x > 1

Combine the intervals

f (x) < 1 or f (x) > 1

x^{3} - 5 x

f (x) = \frac{( 3 x - 1 )}{2 x + 5}

y = 3 x^{6} - x^{8}

4 x - 2 - 6

x + 6 y = 12

What is the range of f(x)=((x-1))/(x+1) ?
The range of f(x)=((x-1))/(x+1) is f(x)<1\lor f(x)>1