What is the range of f(x)=x^2-25,x>= 5 ?

The range of f(x)=x^2-25,x>= 5 is f(x)>= 0

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range of f(x)=x^2-25,x>= 5

range

f (x) = x^{2} - 25, x \geq 5

f (x) \geq 0

Interval Notation

[0, \infty)

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

x^{2} - 25, x \geq 5 : x \geq 5

Extreme Points of

x^{2} - 25, x \geq 5 :

Minimum

(5, 0)

Find the range for the interval

5 \leq x < \infty : 0 \leq f (x) < \infty

Combine the ranges of all domain intervals to obtain the function range

f (x) \geq 0

(x - 8)^{2}

f (x) = \frac{1}{x + 1}

3 cos (5 x - 9)

x^{2} + 4 x + 7

3 cot (2 π x)

What is the range of f(x)=x^2-25,x>= 5 ?
The range of f(x)=x^2-25,x>= 5 is f(x)>= 0