What is the derivative of-sin(x+cos(x)) ?

The derivative of-sin(x+cos(x)) is -cos(x)-sin(x)

What is the first derivative of-sin(x+cos(x)) ?

The first derivative of-sin(x+cos(x)) is -cos(x)-sin(x)

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\frac{d}{d x} (- sin (x) + cos (x))

- cos (x) - sin (x)

Solution steps

\frac{d}{d x} (- sin (x) + cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (sin (x)) + \frac{d}{d x} (cos (x))

\frac{d}{d x} (sin (x)) = cos (x)

\frac{d}{d x} (cos (x)) = - sin (x)

= - cos (x) - sin (x)

f (x) = (6 x^{2} + 4) e^{x}

\int \frac{x}{x ^{2} + 6 x + 11} d x

\frac{d}{d x} ((5 - 3 x)^{3})

e^{6 e^{x}}

\int_{0}^{1} (2 x - 2 x^{2}) d x

What is the derivative of-sin(x+cos(x)) ?
The derivative of-sin(x+cos(x)) is -cos(x)-sin(x)
What is the first derivative of-sin(x+cos(x)) ?
The first derivative of-sin(x+cos(x)) is -cos(x)-sin(x)