What is the solution for y^'-2/x y=(y^5)/(x^2),y(1)=1 ?

The solution for y^'-2/x y=(y^5)/(x^2),y(1)=1 is y=(\sqrt[4]{7}x^2)/(\sqrt[4]{-4x^7+11)}

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y^'-2/x y=(y^5)/(x^2),y(1)=1

y^{^{'}} - \frac{2}{x} y = \frac{y ^{5}}{x ^{2}}, y (1) = 1

Solution steps

y^{'} (x) - \frac{2}{x} y = \frac{y ^{5}}{x ^{2}}

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What is the solution for y^'-2/x y=(y^5)/(x^2),y(1)=1 ?
The solution for y^'-2/x y=(y^5)/(x^2),y(1)=1 is y=(\sqrt[4]{7}x^2)/(\sqrt[4]{-4x^7+11)}