What is the limit as x approaches 9 of 1/(sqrt(x)+3) ?

The limit as x approaches 9 of 1/(sqrt(x)+3) is 1/6

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limit as x approaches 9 of 1/(sqrt(x)+3)

x \to 9 lim (\frac{1}{x + 3})

\frac{1}{6}

Decimal Notation

0.16666 \dots

Solution steps

x \to 9 lim (\frac{1}{x + 3})

Plug in the value

x = 9

= \frac{1}{9 + 3}

Simplify

\frac{1}{9 + 3} : \frac{1}{6}

= \frac{1}{6}

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What is the limit as x approaches 9 of 1/(sqrt(x)+3) ?
The limit as x approaches 9 of 1/(sqrt(x)+3) is 1/6