What is area y=x,y=2xsqrt(25-x^2) ?

The answer to area y=x,y=2xsqrt(25-x^2) is 567/4

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area y=x,y=2xsqrt(25-x^2)

area

y = x, y = 2 x 25 - x^{2}

\frac{567}{4}

Decimal Notation

141.75

Solution steps

Apply the area formula:

\int_{- \frac{3 11}{2}}^{\frac{3 11}{2}} x - 2 x 25 - x^{2} d x

Solve

\int_{- \frac{3 11}{2}}^{\frac{3 11}{2}} x - 2 x 25 - x^{2} d x : \frac{567}{4}

The area is:

= \frac{567}{4}

\int_{- 2}^{2} - 2 x^{2} + 8 d x

f (x) = \frac{- 2}{x ^{2}}

\frac{1}{x ^{2} + 18 x + 88}

y = x (x - 4)

\int - \frac{1}{2} cos (2 x) (2 x) d x

What is area y=x,y=2xsqrt(25-x^2) ?
The answer to area y=x,y=2xsqrt(25-x^2) is 567/4