What is (\partial)/(\partial x)(2ye^{4x}) ?

The answer to (\partial)/(\partial x)(2ye^{4x}) is 8e^{4x}y

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(\partial)/(\partial x)(2ye^{4x})

\frac{\partial}{\partial x} (2 y e^{4 x})

8 e^{4 x} y

Solution steps

\frac{\partial}{\partial x} (2 y e^{4 x})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 y \frac{\partial}{\partial x} (e^{4 x})

Apply the chain rule:

e^{4 x} \frac{\partial}{\partial x} (4 x)

= e^{4 x} \frac{\partial}{\partial x} (4 x)

\frac{\partial}{\partial x} (4 x) = 4

= 2 y e^{4 x} \cdot 4

Simplify

= 8 e^{4 x} y

\int (80 - 3 t - (2 t + 30)) d t

\frac{d}{d x} (\frac{x - x ^{2}}{2 - 3 x + x ^{2}})

\int_{0}^{l n (6)} e^{x} - e^{- 3 x} d x

y = \frac{4 x}{9 - tan ( x )}

arctan (x)

What is (\partial)/(\partial x)(2ye^{4x}) ?
The answer to (\partial)/(\partial x)(2ye^{4x}) is 8e^{4x}y