What is the derivative of 3/(x^3)-1/(x^4) ?

The derivative of 3/(x^3)-1/(x^4) is -9/(x^4)+4/(x^5)

What is the first derivative of 3/(x^3)-1/(x^4) ?

The first derivative of 3/(x^3)-1/(x^4) is -9/(x^4)+4/(x^5)

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derivative of

\frac{3}{x ^{3}} - \frac{1}{x ^{4}}

- \frac{9}{x ^{4}} + \frac{4}{x ^{5}}

Solution steps

\frac{d}{d x} (\frac{3}{x ^{3}} - \frac{1}{x ^{4}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{3}{x ^{3}}) - \frac{d}{d x} (\frac{1}{x ^{4}})

\frac{d}{d x} (\frac{3}{x ^{3}}) = - \frac{9}{x ^{4}}

\frac{d}{d x} (\frac{1}{x ^{4}}) = - \frac{4}{x ^{5}}

= - \frac{9}{x ^{4}} - (- \frac{4}{x ^{5}})

Simplify

= - \frac{9}{x ^{4}} + \frac{4}{x ^{5}}

(26 \frac{2}{3}, 9), (5, 2.5)

x \to 0 lim (x^{2} cos (x))

f (x) = \frac{5}{x}, at x = 5

\int \frac{3 x}{x + 1} d x

\int 64 cos^{4} (8 x) d x

What is the derivative of 3/(x^3)-1/(x^4) ?
The derivative of 3/(x^3)-1/(x^4) is -9/(x^4)+4/(x^5)
What is the first derivative of 3/(x^3)-1/(x^4) ?
The first derivative of 3/(x^3)-1/(x^4) is -9/(x^4)+4/(x^5)