What is the integral from 1 to 2 of (e^x)/x ?

The integral from 1 to 2 of (e^x)/x is \Ei(2)-\Ei(1)

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integral from 1 to 2 of (e^x)/x

\int_{1}^{2} \frac{e ^{x}}{x} d x

Ei (2) - Ei (1)

Solution steps

\int_{1}^{2} \frac{e ^{x}}{x} d x

Use the nonelementary integral:

\int \frac{e ^{x}}{x} d x = Ei (x)

= [Ei (x)]_{1}^{2}

Compute the boundaries:

Ei (2) - Ei (1)

= Ei (2) - Ei (1)

(7.2) (2.12)

x^{3}, 0, 1

\int \frac{3}{e ^{3 x}} d x

\int_{4}^{e^{3}} \frac{1}{x} d x

\frac{\partial}{\partial y} (cos (x + 4 y))

What is the integral from 1 to 2 of (e^x)/x ?
The integral from 1 to 2 of (e^x)/x is \Ei(2)-\Ei(1)