What is the derivative of 3x^2-24x+45 ?

The derivative of 3x^2-24x+45 is 6x-24

What is the first derivative of 3x^2-24x+45 ?

The first derivative of 3x^2-24x+45 is 6x-24

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\frac{d}{d x} (3 x^{2} - 24 x + 45)

6 x - 24

Solution steps

\frac{d}{d x} (3 x^{2} - 24 x + 45)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (24 x) + \frac{d}{d x} (45)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (24 x) = 24

\frac{d}{d x} (45) = 0

= 6 x - 24 + 0

Simplify

= 6 x - 24

\frac{d}{d x} (x^{3} + 3 x^{2} - 1)

θ \to + 0 lim (\frac{tan ( 2 θ )}{θ})

x \to 3 + lim (\frac{x - 3}{x - 2 - 4 - x})

n = 1 \sum \infty i^{2 n}

n = 2 \sum \infty n (\frac{3}{4})^{n}

What is the derivative of 3x^2-24x+45 ?
The derivative of 3x^2-24x+45 is 6x-24
What is the first derivative of 3x^2-24x+45 ?
The first derivative of 3x^2-24x+45 is 6x-24